If the point of intersections of the ellipse $\frac{ x ^{2}}{16}+\frac{ y ^{2}}{ b ^{2}}=1$ and the circle $x ^{2}+ y ^{2}=4 b , b > 4$ lie on the curve $y^{2}=3 x^{2},$ then $b$ is equal to:

  • [JEE MAIN 2021]
  • A

    $12$

  • B

    $5$

  • C

    $6$

  • D

    $10$

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  • [JEE MAIN 2021]